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- Mon Jul 30, 2007 12:45 pm
- Forum: Power-producing Stirling Engines
- Topic: power output
- Replies: 2
- Views: 12673
Response to power output
<r>Using Brent's extremely simple and correct method:<br/> <br/> w = d * m * 9.81 / t <br/> <br/> where d = distance, expressed in metres that the weight was lifted; m = mass of the weight, expressed in kilogram; t = time it took to lift the weight, expressed in seconds; 9.81 = gravity constant, m/s...